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What least number must be added to 1056 to get a number exactly divisible by 23? |
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Answer» 1056 ÷ 23 , quotient = 45, remainder = 19 Since remainder is not zero. So, 1056 is not exactly divisible by 23 So, we take next multiple of 23. Next multiple = 46 So, 23 * 46 = 1058 So, 1058 is exactly divisible by 23 . 1958 - 1056 = 2 |
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