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What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in case the same remainder 7?1). 132). 363). 394). 30 |
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Answer» ? The number should be divisible by 9, 10 and 15 leaving a remainder of 7 in each case. Thus a remainder of 7 will be ALSO obtained when it is divided by the LCM of 9, 10 and 15. LCM of 9, 10 and 15 = 90 Dividing 1936 by 90 we GET, Quotient = 21 Remainder = 46 The remainder should be 7 Thus LEAST number which should be subtracted from 1936 = 46 – 7 = 39. |
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