1.

What mass (in mg) of available O_(2) per liter is present in the a solution of H_(2)O_(2) 10 mL of which when treated requires 25 mL of N/20 KMnO_(4) for complete oxidation of it

Answer»


Solution :The given REACTION is
`2KMnO_(4) + 5H_(2)O_(2) + 4H_(2)SO_(4) to 2KHSO_(4) + 2MnSO_(4) + 8H_(2)O + 5O_(2)`
meq. Of `O_(2)` =MEG . Of `H_(2)O_(2) =` meq. Of `KMnO_(4)`
`Nxx10=25xx1/20`
`:. N_(H_(2)O_(2)) =25/200 =0.125 rArr N_(O_(2))=0.125`
or `W_(O_(2))=0.125xx16 =2g//L`


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