What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? (Y=2xx10^(11)Nm^(-2))

What mass must suspended from the free end of a steel wire of length 2

1.	What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? (Y=2xx10^(11)Nm^(-2))
Answer» Solution :`r = 1/2 xx 10^(-3) m , L = 2m, Y = (Mg)/(PI r^2) L/e` `M = (Y(pi r^2)e)/(gL) = (2 xx 10^11 xx pi (1/2 xx 10^(-3))^2 xx 1 xx 10^(-3))/(9.8 xx 2)` ` = (pi xx 10^2 )/(9.8 xx 4) = (100pi)/(39.2) = 8.015 kg `