1.

What mass of Agl will dissolve in 1.0L of 1.0M NH_3 ? Neglect change in conc. NH_3[ Given , K_(sp) (Agl) =1.5 xx 10^(-16),K_f [Ag(NH_3) _2^(+)] =1.6 xx 10^(7)], (At .Wt . Ag =108 , 1 =127)

Answer»

`4.9 xx 10^(-5) g`
` 0.0056 g`
` 0.035 g`
` 0.011 g`

Solution :Due to higher value of `K_f` mostly `Ag^(+) `converted in to complex.
` K_(SP). K_f =(X^(2))/( (Z-2x)^(2) ) `
` 1.6 xx 10^(7)xx 1.5 xx10^(-16) =(x^(2))/((1-2x)^(2))`
but ` 1-2x ~~ 1, x =4.9xx 10 ^(5)" mol " //lit `
Mass of ` Agl =4.9 xx 10 ^(-5)xx 235 =0.011 gm`


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