1.

What mass of Barium chloride is required to react with 48.6 grams of sodium phosphate according to the following reaction: 2 Na3PO4 + 3BaCl2 → Ba3(PO4)2 + 6 NaCl​

Answer»

92.6 G of BaCl2Explanation:The ANSWER is 92.6 g of BACL 2



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