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What mass of ethylene glycol (molar mass = 62.0 g mol^(-1) ) must be added to 5.50 kg of water to lower the freezing point of water from 0^(@)Cto - 10.0^(@) C ? (K_(f) "for water " = 1.86 k " kg mol"^(-1)) |
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Answer» Solution :`W_(B)= ?, M_(B) = 62 , W_(A) = 5.50 G ` `Delta T_(f) = 10^(@) C, K_(f) = 1.86` `Delta T_(f) = K_(f) xx (W_(B))/(M_(B) xx W_(A))` 10 = `1.86 xx (W_(B))/(62 xx 5.50) ` 3410 = 1.86`W_(B)` `W_(B) = ` 1833.3 = 1.833 KG |
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