1.

What mass of hydrochloric acid is needed to decompose 50 g of limestone?A. 36.5 gB. 73 gC. 50 gD. 100 g

Answer» `underset(100g)(CaCO_3)+underset(2xx36.5=73g)(2HCl) to CaCl_2 + H_2O +CO_2`
100 g of `CaCO_3` required 73 g of HCl
`therefore` 50 g of `CaCO_3 " requires " 73/100xx50=36.5` g of HCl


Discussion

No Comment Found

Related InterviewSolutions