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What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution ? Calculate the mass of oxygen will be liberated by the decomposition of 200 mL of this solution . |
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Answer» Solution :Mol. Mass of `H_(2)O_(2)=34 g "mol"^(-1)` `therefore 1 L` of M solution of `H_(2)O_(2)` will contain `H_(2)O_(2)=34xx5` g `therefore 2 `L of 5 M solution will contain `H_(2)O_(2)=34xx5xx2=340 g` or 200 mL of 5 solution will contain `H_(2)O_(2)=(340)/(2000)xx200=34` g Now`underset(68 g)(2H_(2)O_(2))to 2H_(2)O + underset(32g)(O_(2))` Now 68 g of `H_(2)O_(2)` on DECOMPOSITION will give `O_(2)=32 g` `therefore 34 g ` of `H_(2)O_(2)` on decomposition will give `O_(2)=(32)/(68)xx34=16` g |
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