1.

What mass of isobutylene is obtained from 37 g of tertiary butyl alcohol by heating with 20% H_(2)SO_(4) at 363 K if the yield of the reaction is 65%?

Answer»

12.8 g
21.8 g
18.2 g
28.1 g

Solution :`(CH_(3))_(3)COH underset(Delta)overset(20% H_(2)SO_(4))to (CH_(3))_(2)C =CH_(2)+H_(2)O`
74 g of t-BUOH give isobutylene = 56 g
`:.` 37 g of t-BuOH will give isobutylene = `(56)/(74) xx 37 = 28 g`
But the yield of the reaction = 65%
`:.` Wt. of isobutylene ACTUALLY formed = `(28 xx 65)/(100)= 18.2g`


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