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What mass of `Na_(2)SO_(4).7H_(2)O` contains exactly `6.023xx10^(22)` atoms of oxygen?

Answer» Molar mass of `Na_(2)SO_(4).7H_(2)O` =275 gm
1 mole `Na_(2)SO_(4).7H_(2)O` has 11 mol O-atoms.
`implies 11 N_(A)O`- atoms are in 275 g `Na_(2)SO_(4).7H_(2)O`
`implies 6.023xx10^(23)O`- atoms are in `=(275)/(11xx6.023xx10^(23))xx6.023xx10^(22)` g=2.5 g


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