1.

What mass of O2 is present in 50.0 g CuSO4SH2O(1) 12.8 g(2) 16.0 g(3) 20. 0 g(4) 28.8 g

Answer»

= Molar mass of CuSO4*5H2O is 249.6850

= 249.6850 g contains ----- 144 g of O2

= 50 grams contain = 50 * 144 / 249.6850 = 28.8 g.



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