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What mass of propene is obtained from 34.0 g of 1- iodopropane on treating with ethanolic KOH , if yield is 36% ? |
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Answer» Solution :`underset("MOL. mass = 170 ") (CH_(3)CH_(2)CH_(2)I ) + KOH ("ethanolic") to underset("Mol. mass = 42 ") (CH_(3)CH = CH_(2) + KI + H_(2)O)` 170 g of 1-iodoform yield = 42 g of propene 34 g of 1-iodoform yield = `42/170 xx 34 ` If the yield is `36%` AMOUNT of propene = `42/170 xx 34 xx 36/100 g = 3.024 g` |
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