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What must be subtracted from 2x24 + 4x2 – 3x + 7 to get 3x3 – x2 + 2x + 1 ? |
Answer» (2x4 + 4x2 – 3x + 7) – Q(x) = 3x3 – x2 + 2x + 1 Q(x) = (2x4 + 4x2 – 3x + 7) – 3x3 – x2 + 2x + 1 The required polynomial = 2x4 + 4x2 – 3x + 7 – 3x3 + x2 – 2x – 1 = 2x4 – 3x3 + 5x2 – 5x + 6 |
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