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What number must be added to each of 45, 13, 33 and 9 such that the resultant numbers are in proportion?1). 42). 33). 134). 12 |
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Answer» Let the number to be added be ‘m’, then according to the question, $(\frac{{45 + m}}{{13 + m}} = \frac{{33 + m}}{{9 + m}})$ ⇒ 405 + 9m + 45m + m2 = 429 + 33m + 13m + m2 ⇒ 54m – 46m = 429 – 405 ⇒ 8m = 24 ⇒ m = 3 Since, the required ANSWER is 3. |
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