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What percentage increase in wavelength leads to `75%` loss of photon energy in a photon-electron collision?A. 200B. 100C. 67D. 300

Answer» Correct Answer - D
Energy of a photons =`(hC)/(lambda)=E, E =0.25 E =(hC)/(lambda)`
So % change in wavelength `=(4lambda-lambda)/(lambda) xx100% =300%`


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