Saved Bookmarks
| 1. |
What percentage increase in wavelength leads to `75%` loss of photon energy in a photon-electron collision?A. 200B. 100C. 67D. 300 |
|
Answer» Correct Answer - D Energy of a photons =`(hC)/(lambda)=E, E =0.25 E =(hC)/(lambda)` So % change in wavelength `=(4lambda-lambda)/(lambda) xx100% =300%` |
|