1.

What quantity of copper(II) oxide will react 2.80litre of hydrogen at NTPA. 79.5 gB. 2 gC. 9.9 gD. 22.4 g

Answer» `underset(79.5g)(CuO)+underset(22.4L)(H_2) to Cu + H_2O`
22.4 L of `H_2 -=` 79.5g of CuO
2.80 L of `H_2 -=(79.5)/(22.4)xx2.80=9.9g` of CuCO


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