1.

What ratio of Pb^(2+) to Sn^(2+) concentration is needed to reverse the following cell reaction ? Sn(s)+Pb^(2+) (aq.) rarr Sn^(2+) (aq.)+Pb(s) E_(Sn^(2+)//Sn)^(@)=-0.136 volt and E_(Pb^(2+)//Pb)^(@)=-0.126 volt

Answer»


ANSWER :`([PB^(2+)])/([SN^(2+)])=0.458`


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