1.

What retardation is to be produced for a motorcycle moving with a velocity of 72km/hr to stop it at distance of 100m ? also calculate the time taken to stop that motorcycle

Answer»

ANSWER:

If the initial velocity being is a straight line, and the final velocity being 0 km/hr, or o m/s, then:

V(final) = v(initial) + at

0 = 72 Km/h + (-=a * 10 s)

- a * 10 s = 72 km/hr * hr/3600s * 1000m/km = 20m/s

a = - (20 m/s) / (10 s)

a = - 2 m/s^2

By retardation I think you mean negative ACCELERATION or DECELERATION. That’s 2 m/s^2.

Explanation:



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