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What shoud be the radius of a capillary tube if the water has to rise to a height of 6 cm in it. Surface of water =7.2xx10^(-2)Nm^(-1) (g=10ms^(-2)) |
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Answer» SOLUTION :Height `(h)=6cm=6XX10^(-2)m` Surface tension of WATER (S)`=7.2xx10^(-2)NM^(-1)` for water `theta=0, cos theta =1` Density of water `(rho)=1000kgm^(-3)` Surface tension `(S)=(HR rho g)/(2 cos theta)` Substituting the values `7.2xx10^(-2)=((6xx10^(-2))(r)(1000)(10))/(2xx1)` `r=0.24xx10^(-3)m` |
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