What should be the maximum average velocity of water in a tube of diameter 2 em so that the flow is laminar ? Viscosity of water is 10^(-3) Ns m^(-2) ? For laminar flow R-1000.

What should be the maximum average velocity of water in a tube of diam

1.	What should be the maximum average velocity of water in a tube of diameter 2 em so that the flow is laminar ? Viscosity of water is 10^(-3) Ns m^(-2) ? For laminar flow R-1000.
Answer» Solution :` "" R = (RHO VR)/( eta) ,v= ( RETA)/( rho r)` ` "" v= ( 1000 xx 10 ^(-3))/( 10^(3) xx 10 ^(-2)) = 0.1 MS^(-1)`