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What should be the pressure inside a small air bubble of `0.1 mm` radius situated just below the surface of water? Surface tension of water `=72xx10^(-3)N//m` and atmospheric pressure `=1.013xx10^(5)N//m^(2)`

Answer» Surface tension of water `T=7.2xx10^(-2) Nm^(-1)`
Radius of air bubble `R=0.1 mm = 10^(-4) m`
The excess pressure inside the air bubble is given by,
`p_(2)-p_(1)=(2T)/(R )`
`therefore` Pressure inside the air bubble, `p_(2)=p_(1)+(2T)/(R )`
Substituting the values, we have
`p_(2)=(1.013xx10^(5))+((2xx7.2xx10^(-2)))/(10^(-4))=1.027xx10^(5)Nm^(-2)`


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