

InterviewSolution
Saved Bookmarks
1. |
What should be the pressure inside a small air bubble of `0.1 mm` radius situated just below the surface of water? Surface tension of water `=72xx10^(-3)N//m` and atmospheric pressure `=1.013xx10^(5)N//m^(2)` |
Answer» Surface tension of water `T=7.2xx10^(-2) Nm^(-1)` Radius of air bubble `R=0.1 mm = 10^(-4) m` The excess pressure inside the air bubble is given by, `p_(2)-p_(1)=(2T)/(R )` `therefore` Pressure inside the air bubble, `p_(2)=p_(1)+(2T)/(R )` Substituting the values, we have `p_(2)=(1.013xx10^(5))+((2xx7.2xx10^(-2)))/(10^(-4))=1.027xx10^(5)Nm^(-2)` |
|