1.

What should be the ratio of concentrations of formate ion and formic acid in a buffer solution so that its pH should be 4? Around what pH will this buffer have maximum buffer capacity?Ka = 1.8 x 10-4?

Answer»

pH = pKa + log\(\frac{[Salt]}{[Acid]}\)

4 = − log(1.8 x 10-4) + log\(\frac{[Formate]}{[Formic\,Acid]}\)

4 = 3∙74 + log\(\frac{[Formate]}{[Formic\,Acid]}\)

log\(\frac{[Formate]}{[Formic\,Acid]}\) = 4- 3.47 = 0.26

\(\frac{[Formate]}{[Formic\,Acid]}\) = 1.8

The buffer capacity of this solution would be maximum near the pKa of the acid.

\(\therefore\) For maximum buffer capacity

pH = pKa = − log Ka

= − log (1∙8 × 10−4)

= 3∙74.



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