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What should be the tension applied to a wire of length 1 m and mass 10 grams, if it has to vibrate with the fundamental frequency of 50 Hz ? |
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Answer» Data : L = 1 m, mass of the wire = 10 g = 0.01 kg, n = 50 Hz ∴ m = mass per unit length of the wire = \(\frac{0.01}1\) = 0.01 kg/m n = \(\frac 1{2L}\)\(\sqrt{\frac Tm}\) ∴ Tension = T = 4n2L2 m = 40(50)2 (1)2 (0.01) = 4 × 2500 × 0.01 = 100 N |
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