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What value of temperature in farenheit scale Becomes half than value in celcius scale ? |
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Answer» Solution :`T_(F)=(9)/(5)T_(C)+32T_(F)=1/2T_(C)` `:.(1)/(2)T_(C)=(9)/(5)T_(C)+32` `:.(9)/(5)T_(C)-(1)/(2)T_(C)=-32` `:.T_(C)=-(320)/(13)` `T_(C)=-24.61" "^(@)C` `:.T_(F)=(T_(C))/(2)` GIVEN, `=-(24.61)/(2)` `=12.305" "^(@)F` |
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