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What value of temperature in farenheit scale becomes double than value in celcius scale ? |
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Answer» Solution :`T_(F)=(9)/(5)T_(C)+32,T_(F)2T_(C)` `:.2T_(C)=9/5T_(C)+32` `:.(T_(C))/(5)=32` `:.T_(C)=160^(@)C` `:.T_(F)=2T_(C)" GIVEN"`, `:.T_(F)=2xx160` `:.T_(F)=320" "^(@)F` |
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