1.

What value of x would make AOB a line if < AOC=4x and 2 BOC=6x+30°6x+30°

Answer»

BOA is a straight lineangle BOC + angle COA = 180 (linear pair)6x + 30 + 4x = 18010x + 30 = 18010x = 180 - 30x = 150/10x = 15

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6x+30+4x=180; 10x+30=180; 10x=180-30=150; x=150/10=15;

4x + 6x + 30 = 180 linear pair

10x + 30 = 18010x = 150x= 15

6(15)+30=1204(15)=60

4x +30+ 6x=18010x+30=180X=150/10X=15

6x+30+4x=18010x+30=180150=10xx=156(15+30)4into 15

6x+30+4x=18010x=180-3010x=150x=150/10x=15



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