What values of b satisfy 3(2b + 3)2 = 36? b = (2√3 - 3)/2,b = (-3√3 - 2)/2,b = (-2√3 - 3)/2, b = (-2√3 + 3)/2

What values of b satisfy 3(2b + 3)2 = 36? b = (2√3 - 3)/2,b = (-3√

1.	What values of b satisfy 3(2b + 3)2 = 36? b = (2√3 - 3)/2,b = (-3√3 - 2)/2,b = (-2√3 - 3)/2, b = (-2√3 + 3)/2
Answer» What values of b satisfy 3(2b + 3)² = 36? Solution: