1.

What volume of 0.157M Nitric acid is needed to neutralize a 25ml of 0.1M NaOH?

Answer»

EXPLANATION:

This is a titration curve question. I know that the initial PH of the hydrochloric acid is 1.65. I know that you can FIND the concentration of HCl by plugging it into the pH FORMULA. So,

log

[

H

+

]

=

1.65

10

1.65

=

0.02239

=

[

H

+

]

.

However, that's as far as I've GOTTEN. I know the volume of the 0.1292 M NaOH is between 22 and 23 mL, but I can't seem to figure out how to find the exact value. Any help is greatly appreciated!



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