1.

What volume of 0.25mol of oxygen occupy at 8.2atm pressure and 127^(@)C according to ideal gas law ?

Answer»

1L
1.5L
0.1L
4.5L

Solution :`V = ( NRT)/( p ) = ( 0.25 XX 0.082 xx 400)/( 8.2 ATM) = 1L`


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