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What volume of 10 M HCl and 3M HCl should be mixed to get 1 L of 6M HCl solution ? |
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Answer» Let the VOLUME of 10 MHCl = x L `:.` the volume of `3MHCl = (1-x)L` `M_(1)V_(1)+M_(2)V_(2)=M_(3)V_(3),10xx x+3xx(1-x)=6xx1` `10x +3-3x=6or7x=3orx=3//7=0.428L` `:.` Volume of 10 MHCl = 0.428 L = 428 mL Volume of 3 M HCl = (1000 - 428)= 573 mL |
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