What volume of 10M HCL and 3M HCL should be mixed to obtain 1L of 6M H

1.	What volume of 10M HCL and 3M HCL should be mixed to obtain 1L of 6M HCL solution?....... !!?
Answer» Suppose volume of 10 M HCl required to prepare 1 L of 6 M HCl = x litre\xa0Volume of 3 M HCl required = (1-x) litre\xa0Applying molarity equation:\xa0Therefore Vol. of 10 M HCl required = 0.428 L = 428 mL.\xa0Vol. of 3 M HCl required = 1-0.428 = 0.527 L = 572 mL

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