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What volume of `2MH_(2)SO_(4)` is required to from 0.2 N of 100 mL of solution ?A. 5 mLB. 20 mLC. 10 mLD. 50 mL |
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Answer» Correct Answer - A `because M-H_(2)SO_(4)=2N-H_(2)SO_(4)` `because2M-H_(2)SO_(4)=4N-H_(2)SO_(4)` `N_(1)V_(1)=N_(2)V_(2)` `4xxV_(1)=0.2xx100` `V_(1)=(0.2xx100)/(4)=5mL.` |
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