What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(3+)`, `HNO_(3)` gets converted to `NO` ?A. `8 mL`B. `16 mL`C. `32 mL`D. `64 mL`

What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(

1.	What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(3+)`, `HNO_(3)` gets converted to `NO` ?A. `8 mL`B. `16 mL`C. `32 mL`D. `64 mL`
Answer» Correct Answer - B Meq.of `HNO_(3)="Meq.of" Fe^(3+)` `["Eq.of" HNO_(3)=M//3]` or `3xx3xxV=(8)/(56)xx1000` `:. V=15.87 mL`

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What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(3+)`, `HNO_(3)` gets converted to `NO` ?A. `8 mL`B. `16 mL`C. `32 mL`D. `64 mL`

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