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What volume of 4M HCl and 2M HCl should be mixed to get 500 mL of 2.5 M HCl ? |
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Answer» Solution :Let the volume of 4M HCl required to prepare 500 mL of `2.5 mL of 2.5M HCl =x ` mL THEREFORE, the required volume of `2M HCl = (500-x)` mL We know from the equation `C _(1) V _(1) + C _(2) V_(2) = C_(3) V_(3)` `(4x ) + 2 ( 500 -x) = 2.5 xx 500` ` 4x + 1000 - 2x = 1250` `2x = 1250 - 1000` `x = (250)/(2) = 125 mL` Hence, volume of 4M HCl required = 125 mL Volume of 2M HCl required `= (500 - 125) mL = 375 mL` |
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