1.

What volume of 5M Na_2SO_4 must be addedto 25 mL of 1M BaCl_2 to produce 10 g of BaSO_4 ?

Answer»

8.58 mL
7.2 mL
10 mL
12 mL

Solution :`Na_2SO_4+BaCl_2 to BaSO_4 + 2NaCl`
No. MOLES of `BaSO_4=w/M=10/233=0.0429`
`THEREFORE " No. of moles of " Na_2SO_4 " NEEDED " = (MxxV)/(1000)`
or `0.0429=(5xxV)/(1000) RARR V=8.58mL`


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