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What volume of 6M HCl and 2M HCl should be mixed to get one litre of 3M HCl? |
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Answer» Solution :Suppose the volume of 6M HCl required to OBTAIN 1L of 3M HCl = XL Volume of 2M HCl required = (1-x)L Applying the molarity equation `M_1 V_1 + M_2V_2 = M_3V_3 ` `6 MHCL + 2MHCl = 3MHCl` `6x+2(1-x) = 3 XX 1` `6x + 2 -2x = 3 ` ` 4X =1 ` `x =0.25 L` HENCE, volume of 6 M HCl rquired = 0.25 L Volume of 2M HCl required = 0.75 L |
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