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What volume of air containing 21percentof oxygen at NTP required to 1lit of so2to so3atNTP

Answer»

Explanation:

21% of oxygen by volume means for 1 L of air volume of oxygen will be 0.21L and as we KNOW 1 mole of ideal GAS OCCUPY 22.4L volume at STP i.e. Standard temperature and pressure. It implies 0.21L of oxygen will have 0.21*(1/22.4) MOLES of oxygen i.e. 0.009375 moles of oxygen and that is your answer.



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