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What volume of carbonmonoxide at 2 atm and 273^(@)C is required in order to produce 5.6 grams of metal by the reduction of ferric oxide? |
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Answer» SOLUTION :Reduction of FERRIC oxide with carbonmonoxide gives iron metal. `Fe_(2)O_(3)+3COrarr3CO_(2)+2Fe` 2 moles of `Fe -= 3` moles of CO 56 grams of `Fe -= 33.6` L of CO at STP 5.6 grams of `Fe -= 3.36` lit of CO at STP The volume of CO required at STP = 33.6 L `{:("STP CONDITIONS","Given conditions"),(P_(1)=1ATM,P_(2)=2atm),(T_(1)=273K,T_(2)=2xx273K),(V_(1)=3.36L,V_(2)=?):}` `V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(1xx3.36xx2xx273)/(273xx2)=3.36L` |
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