What volume of ethane (NTP; 1 bar, 273 K) is formed from 38 g of sodium propionate by fusion with sode lime?

What volume of ethane (NTP; 1 bar, 273 K) is formed from 38 g of sodiu

1.	What volume of ethane (NTP; 1 bar, 273 K) is formed from 38 g of sodium propionate by fusion with sode lime?
Answer» 8.87LExplanation:Reaction of sodium carboxylate with sodalime is called sodalime decarboxylation reaction - Reaction is as follows:RCH₂COONa + NaOH → RCH₃ + Na₂CO₃ (in the presence of CAO which HELPS in keeping NaOH DRY)ACCORDING to given QUESTION,CH₃CH₂COONa + NaOH → CH₃CH₃ + Na₂CO₃1 mole of CH₃CH₂COONa = 1 mole of CH₃CH₃or, 38/96 mole of CH₃CH₂COONa = 38/96 mole of CH₃CH₃We know that at NTP, 1 mole gases occupy a volume of 22.4LSo, 38/96 mole of CH₃CH₃ will occupy a volume = 38 x 22.4/96 L = 8.87L