What volume of H_(2) at NTP is required to convert 2.8 g of N_(2) into

1.	What volume of H_(2) at NTP is required to convert 2.8 g of N_(2) into NH_(3)?
Answer» 2240 ml 22400 ml 6.72 lit 224 lit Solution :`N_(2)+3H_(2)rarr2NH_(3)` `28grarr3xx22.4` lit `2.8g RARR? =3xx22.4xx0.1=6.72` lit

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