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What volume of hydrogen at N.T.P would be liberated by the action of 50 mL of dilute `H_(2)SO_(4)` of 40 % purity and having a specific gravity of `1.3 g mL^(-1)` on 65 g of zinc ? (Atomic mass of Zn = 65). |
Answer» Step I. Calculation of mass of pure `H_(2)SO_(4)` Mass of 50 mL of dilute `H_(2)SO_(4)` = Volume `xx` Specific gravity `= 50 mL xx (1.3 "g mL"^(-1))=65` g 100 g of `H_(2)SO_(4)` solution contain pure acid = 40 g 65 g of `H_(2)SO_(4)` solution contain pure acid `= (40)/(100) xx 65 g = 26 g`. Step II. Calculate of volume of hydrogen evolved at N.T.P The reaction involved is : `{:("Zn"+,H_(2)SO_(4),rarr,ZnSO_(4)+,H_(2)),(65g,2xx1+32+4xx16,,,22.4 L),(,=98g,,,"at N.T.P."):}` 98 g of `H_(2)SO_(4)` evolve `H_(2)` at N.T.P. = 22.4 L 26 g of `H_(2)SO_(4)` evolve `H_(2)` at N.T.P `= (22.4)/(98) xx 26g = 5.94 L`. |
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