1.

What volume of hydrogen at STP required to reduce 7.95 grams of cupric oxide to give metal?

Answer»

SOLUTION :CUPRIC oxide is reduced to copper on treating with hydrogen
`CuO+H_(2)to Cu+H_(2)O`
1 mole of CuO =1 mole of `H_(2)`
79.5 grams of CuO=22.4 L of `H_(2)` at STP
7.95 grams of CuO=?
VOLUME of hydrogen required at STP `=(7.95)/(79.5) XX 22.4=2.24L`


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