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What volume of O_(2) is liberated at STP by warning 3.4 g of hydrogen peroxide ? |
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Answer» Solution :`2H_(2)O_(2)to2H_(2)O+O_(2)` `2xx34g` of `H_(2)O_(2)` can LIBERATE `22.4L` of `O_(2)` at STP. `3.4g` of `H_(2)O_(2)=(3.4xx22.4)/(2xx34)=1.12L` of `O_(2)` at STP. |
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