1.

What volume of oxygen (NTP) will be required to react with 1 g of Ca?

Answer»

Solution :As Ca combines with `O_(2)` to give CaO , from the FORMULA of CaO,
We have
moles of Ca = moles of O (atoms)
`(wt. of Ca)/( at . wt.) = ("vol . of O atoms at NTP")/("vol . OCCUPIED by 1 moleof O ATOMSOF NTP")`
`(1)/(40)= (vol . of O)/( 11.2)`
` :. ` vol of O = `(11.2)/( 40) = 0 . 28` litre.


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