What was the expression for trigonometrical function sin x? – InterviewSolution

1.

What was the expression for trigonometrical function sin x?

Answer»

The expression for trigonometrical function sin x in Mahabhashkariya was given as.

\(\frac{Sin\,x\,=\,16x(\pi\, -\, x)}{5\pi^2\,-\,4\pi(\pi-x)}\)

0 ≤ x ≤ \(\frac{\pi}{2}\).

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