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What weight of calcium has the same number of atoms as are present in 3.2g of sulphur ? |
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Answer» Gram atomic mass of S=32g 32g of sulphur contain atoms=`6.022xx10^(23)` 3.2g of sulphur contains atoms=`(6.022xx10^(23))/(32g)=6.022xx10^(22)` Step-II: Weight of `6.022xx10^(22)` atoms of calcium Gram atomic mass of Ca=40g `6.022xx10^(23)` atomic of Ca weigh=40g `6.022xx10^(22)` atoms of Ca weigh=`(40g)/(6.022xx10^(23))xx6.022xx10^(22)=4g` |
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