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What weight of calcium the same number of atoms as are present in 3.2g of sulphur ? |
Answer» Step I : No. of atoms in 3.2 g of sulphur Gram atomic mass of `S = 32` g 32 g of sulphur atoms `= 6.022 xx 10^(23)` 3.2 g of sulphur contain atoms `= (6.022xx10^(23))/((32g))xx(3.2g)=6.022xx10^(22)` Step II. Weight of `6.022 xx 10^(22)` atoms of calcium Gram atomic mass of Ca = 40 g `6.022 xx 10^(23)` atoms of Ca weigh = 40 g `6.022 xx 10^(22)` atoms of Ca weigh `= ((40g))/(6.022xx10^(23))xx6.022xx10^(22)=4g`. |
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