1.

What weight of CO_(2) will contain same number of oxygen atoms as are present in 3.6 g of water ?

Answer»

8.8 g
7.2 g
4.4 g
220 g

Solution :No. of WATER molecules in 3.6 g of water
` = (3.6)/(18) XX 6 xx 10^23 ` molecules
` = 1.2 xx 10^23 ` molecules
No. of OXYGEN atoms
` = 1.2 xx 10^23`
Now ` 2 xx 6 xx 10^23` atoms of oxygen in `CO_2`
= 44G
`1.2 xx 10^23` atoms of oxygenin `CO_2`
` = (44)/(2 xx 6 xx 10^23)xx 1.2 xx 10^23`
4.4 g


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