1.

What weight of copper will be deposited by passing 2 Faraday's of electricity through a cupric salt (Atomic weight of Cu = 63.5)

Answer»

`2.0g`
`3.175 G`
`63.5 g`
`127.0 g`

Solution :`CU^(2+) + 2e^(-) to Cu`
2 Faraday.s will DEPOSITE 1g ATOM of Cu = 63.5 g.


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